(x^2+2x-3)-(x^2+3x-4)=

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Solution for (x^2+2x-3)-(x^2+3x-4)= equation:


Simplifying
(x2 + 2x + -3) + -1(x2 + 3x + -4) = 0

Reorder the terms:
(-3 + 2x + x2) + -1(x2 + 3x + -4) = 0

Remove parenthesis around (-3 + 2x + x2)
-3 + 2x + x2 + -1(x2 + 3x + -4) = 0

Reorder the terms:
-3 + 2x + x2 + -1(-4 + 3x + x2) = 0
-3 + 2x + x2 + (-4 * -1 + 3x * -1 + x2 * -1) = 0
-3 + 2x + x2 + (4 + -3x + -1x2) = 0

Reorder the terms:
-3 + 4 + 2x + -3x + x2 + -1x2 = 0

Combine like terms: -3 + 4 = 1
1 + 2x + -3x + x2 + -1x2 = 0

Combine like terms: 2x + -3x = -1x
1 + -1x + x2 + -1x2 = 0

Combine like terms: x2 + -1x2 = 0
1 + -1x + 0 = 0
1 + -1x = 0

Solving
1 + -1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1

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